Absolute difference of the sum across the diagonalsD:424

You are given a square matrix of size N×N. Calculate the absolute difference of the sums across the two main diagonals.

Input Format:
The first line will contain the value of N.
The next N lines will contain the N values separated by one or more spaces.

Output Format:
The absolute difference of the sums across the two main diagonals.

Boundary Conditions:
2 <= N <= 20

Example Input/Output 1:
Input:
2
10 9
4  22

Output:
19

Explanation:
The sum along the first diagonal is 10+22 = 32
The sum along the first diagonal is 4+9=13
The absolute difference is 32-13= 19

Example Input/Output 2:
Input:
2
-10 6
4  -22

Output:
22

PROGRAM IN C:

#include <math.h>

#include <stdio.h>

#include <string.h>

#include <stdlib.h>

#include <assert.h>

#include <limits.h>

#include <stdbool.h>

int main()

{

    int n,sum=0,i,j,sum1=0,to=0;

    scanf("%d",&n);

    int a[100][100];

    for(i=0;i<n;i++)

    {

        for(j=0;j<n;j++)

        {

            scanf("%d",&a[i][j]);

        }   

    }   

    for(i=0;i<n;i++)   

    {

        for(j=0;j<n;j++)

        {

            if(i==j)

             sum=sum+a[i][j]; 

        }   

    }

    for(i=0;i<n;i++)   

     {

         for(j=0;j<n;j++)

         {

             if(i==n-j-1)

             sum1=sum1+a[i][j];

         }

    }

    if(sum<0)

    {

        sum=-sum;

    }

    if(sum1<0)

    {

        sum1=-sum1;

    }

    to=sum-sum1;

    printf("%d",abs(to));

    return 0;

}