Replace Matrix Zeroes with Characters ID:5405

An integer matrix M of size R*C is given as input. A string S is also passed as the input. The program must replace the occurrences of 0 (zero) in the matrix M with the characters in string S in their of order of occurrence and print the resulting matrix as the output.

Boundary Condition(s):
2 <= R, C <= 100

Input Format:
The first line contains the value of R and C separated by space(s).
The next R lines contain the C integer values each representing the matrix M.
The next line contains the string S.

Output Format:
The first line contains C integers separated by a space.

Example Input/Output 1:
Input:
4 5
27 3 0 3 9
11 7 10 13 29
5 31 0 12 17
27 16 20 0 8
machine

Output:
27 3 m 3 9
11 7 10 13 29
5 31 a 12 17
27 16 20 c 8

Example Input/Output 2:
Input:
6 5
0 1 19 24 16
35 27 33 3 6
26 8 10 12 5
19 0 22 10 24
35 8 18 0 13
3 21 12 25 0
magnificient

Output:
m 1 19 24 16
35 27 33 3 6
26 8 10 12 5
19 a 22 10 24
35 8 18 g 13
3 21 12 25 n

PROGRAM IIN C:

 #include<stdio.h>

#include<stdlib.h>

int main()

{

int a,b;char x[100];int k=0;scanf("%d %d",&a,&b);

int c[a][b];

for(int i=0;i<a;i++)

{

    for(int j=0;j<b;j++)

    {

        scanf("%d",&c[i][j]);

    }

}

scanf("%s",x);

for(int i=0;i<a;i++)

{

    for(int j=0;j<b;j++)

    {

        if(c[i][j]==0)

        {

            printf("%c ",x[k]);

            k++;

        }

        else

        {

            printf("%d ",c[i][j]);

        }

    }

    printf("\n");

}

}