Adding reversed numbers ID:220

A pair of numbers (X and Y) will be passed as input. The program must reverse the numbers and find the sum S. Then the sum S must be reversed and printed as output.

- If any leading zeroes are obtained while reversing any of the numerical values they should be discarded.

Boundary Conditions:
0 < X < 10000
0 < Y < 10000

 

Input Format:
First line will contain the value of X
Second line will contain the value of Y

Output Format:
The first line will contain the sum S

Sample Input/Output:

Example 1:
Input:
24
1

Output:
34

Explanation:
24 when reversed is 42. So 42+1 = 43.
When 43 is reversed it is 34 and hence 34 is the output.

Example 2:
Input:
305
794

Output:
1

Explanation:
305 and 794 when reversed are 503 and 497.
503+497 = 1000.
1000 when reversed is 1 which is printed as output.

PROGRAM IN C:

 #include <stdio.h>

int main(){

    int N, a, b, sum, revA, revB, revS;

    

        sum = 0, revA = 0, revB = 0, revS = 0;

        scanf("%d %d", &a, &b);

        while(a){

            revA = (revA*10) + (a%10);

            a /= 10;

        }

        while(b){

            revB = (revB*10) + (b%10);

            b /= 10;

        }

        revS = revA + revB;

        while(revS){

            sum = (sum*10) + (revS%10);

            revS /= 10;

        }

        printf("%d\n", sum);

    return 0;

}